Question

(x - 2x² + 3x – 4) (x - 1) - (2x - 3)(x² - x + 1)​

Answer 1

Step-by-step explanation:

(x3 – 2x2 + 3x – 4) (x – 1) – (2x – 3) (x2 – x + 1) = x4 – 2x3 + 3x2 – 4x – x3 + 2x2 – 3x + 4 – (2x3 – 2x2 + 2x – 3x2 + 3x – 3) = x4 – 3x3 + 5x2 – 7x + 4 – 2x3 + 5x2 – 5x + 3 = x4 – 5x3 + 10x2 – 12x + 7Read more on Sarthaks.com - https://www.sarthaks.com/630337/simplify-x-3-2x-2-3x-4-x-1-2x-3-x-2-x-1

Answer 2

$\sf\bold{\purple{solution \: :-}}$

(x - 2x² + 3x – 4) (x - 1) - (2x - 3)(x² - x + 1)

= (4x - 2x² - 4) (x - 1) - (2x - 3)(x² - x + 1)

= 4x²- 2x³- 4x - 4x + 2x² + 4 - 2x³ - 2x² + 2x - 3x² + 3x -3

= 4x² - 3x + 1