Question

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Answer 1

Since 3b2=35–2a2 is odd and at most 35 , b must be odd and b2<12 . Thus, b=±1 or ±3 .

If b=±1 , then a=±4 . If b=±3 , then a=±2 .

There are eight solutions (a,b) , with a,b∈Z .

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