Question

Answer it

j2+6j+5

factorize

Answer 1

Answer:

$\displaystyle{p ( x ) =(j+5)(j+1)$

Explanation:

Given :

$\displaystyle{p ( x ) = j^2 + 6 j + 5}$

We have to factorize it

By splitting mid term method we have

$\displaystyle{p ( x ) = j^2 + 6 j + 5}\\\\\displaystyle{p ( x ) = j^2 +5j+j+5}\\\\\displaystyle{p ( x ) =j(j+5)+(j+5)}\\\\\displaystyle{p ( x ) =(j+5)(j+1)$

For zeroes of p ( x )

$\displaystyle{p ( x ) =(j+5)(j+1)=0}\\\\\displaystyle{(j+5)=0 \ or \ (j+1)=0}\\\\\displaystyle{j=-5 \ or \ j = -1}$

Thus we factorized the p ( x ) and get zeroes too.

Answer 2

QUESTIONS-

Factorise j² + 6j + 5

$\bf\huge\boxed{Answers}$

Given -

j² + 6j + 5 =0

Solution:

Spilitting middle term

=> j² + 5j + j + 5=0

=> j(j+5) +1(j+5)=0

=> (j+5)(j+1)=0

Two equation solving we will get

j+5=0. | j+1=0

j= - 5 & j= - 1

Therefore the factors of the equations are -5 & - 1

☺☺☺Be_STARS☺☺☺