Question

answer it


just divide it ​

Answer 1

Step-by-step explanation:

$\frac{ {x}^{2} - 6x + 9}{(x - 3)} \\ hey \: if \: we \: observe \: numerator \: \\ we \: will \: find \: that \: it \: is \: perfect \: square \\ \frac{ {(x - 3)}^{2} }{(x - 3)} \\ \frac{(x - 3)(x - 3)}{(x - 3)} \\ (x - 3) \\ \\ hope \: it \: helps \: uh$

Answer 2

$\huge\underline\purple{\sf \: SOLUTION :-}$

GIVEN EQUATION :-

$\frac{( {x}^{2} + 9 - 6x)}{(x - 3)}$

Firstly on solving the numerator...

$( {x}^{2} + 9 - 6x) = {x}^{2} - (3 + 3)x + 9$

$( {x}^{2} + 9 - 6x) = {x}^{2} - 3x - 3x + 9$

$( {x}^{2} + 9 - 6x) = x(x - 3) - 3(x - 3)$

$( {x}^{2} + 9 - 6x) = (x - 3)(x - 3)$

Now putting the solved value of numerator in the equation...

$\frac{( {x}^{2} + 9 - 6x)}{(x - 3)} = \frac{(x - 3)(x - 3)}{(x - 3)}$

$\frac{( {x}^{2} + 9 - 6x)}{(x - 3)} = (x - 3)$

Answer...

HOPE IT HELPS SISTA ✌