Math, asked by sakshi9953, 11 months ago

answer it........not in short.........give full answer

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Answers

Answered by Anonymous
3

Area of Δ ABC = 1/2 Base * altitude

= 1/2 AC * BE = 1/2 AB * CF = 1/2 AB * BE, given BE = CF

So AC = AB

Hence it is an isosceles Δ.

=================================


Consider the triangles ABE and ACF.

Angle A is common. angle BEA = 90 = angle CFA. The triangles are similar.


AB/BE = AC/CF,\ \ \ \ but BE = CF \\ \\ AB = AC


So isosceles triangle.



Read more on Brainly.in - https://brainly.in/question/38629#readmore


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Answered by neharout
4

Area of Δ ABC = 1/2 Base * altitude


= 1/2 AC * BE = 1/2 AB * CF = 1/2 AB * BE, given BE = CF


So AC = AB


Hence it is an isosceles Δ.


=================================



Consider the triangles ABE and ACF.


Angle A is common. angle BEA = 90 = angle CFA. The triangles are similar.



AB/BE = AC/CF,\ \ \ \ but BE = CF \\ \\ AB = AC



So isosceles triangle


Read more on Brainly.in - https://brainly.in/question/5380477#readmore


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