Question

density of gaseous mixture A and b from percentage volume is given by

Answer 1

Answer : The correct option is (3) $d_{mix} =\frac{d_{A} \times percent(A) + d_{B} \times percent (B)}{100}$

Explanation :

Step 1 : Find masses of A and B using % volume

In order to find the density of a mixture, we first need to find the masses of individual substances A and B.

The mass and density are related by following formula.

$mass = density \times volume$

$m_{A} = d_{A} \times percent (A)$

$m_{B} = d_{B} \times percent (B)$

We can see that option 2 and 3 show calculation for mass by multiplying density with volume.

Step 2 : Find total mass

The total mass of the mixture would be

$m_{mix} = d_{A} \times percent(A) + d_{B} \times percent (B)$

Step 3 : Find density of the mixture.

The total volume of the mixture would be 100%.

The density of the mixture is calculated as,

$d_{mix} =\frac{d_{A} \times percent(A) + d_{B} \times percent (B)}{100}$

This is similar to option (3). Therefore the correct answer is $d_{mix} =\frac{d_{A} \times percent(A) + d_{B} \times percent (B)}{100}$

Answer 2

Answer: the answer is written down by the another person but I am just telling to understand that answer the concept applied behind that is this

Case 1 if equal volume of two liquid of density D1 and D2 are mixed together then density of D of mixture is d=D1+D2/2

Case 2 if equal mass of two liquid of density D1 and D2 are mixed together then the density of the of the mixture will be d=2d1+D2/D1+d2

so this was the concept applied and the answer is as there

Explanation: