Question

answer it please...​

Answer 1

in the given fig. TB and TA are the tangents to the circle

so angleATB=2 angle OBA

angle OBA=angleATB/2

angleOBA=80/2

OBA=40

then here TBO =90°

as the point of contact makes normal with the radius

angle TBA=angleOBT -angle OBA

TBA=90°-40°

TBA=50°