Construct a ∆ABC in which AB = 4.8 cm, BC = 5 cm and CA = 5.4 cm
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Answer:
First draw a base line of AB 4.8 cm
Then make centre A and draw 5.4 cm circle arc
Next make center B and draw 5 cm circle arc
Both the arc will intersect at a point
Just join it and make triangle ABC
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