Math, asked by NISHANT2022, 5 months ago

answer it please no galat answer ​

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Answered by anushitripathi09
3

Answer:

20:27

Step-by-step explanation:

there are 2 cylinders...

radius of first cylinder = 2x

r of second cylinder= 3x

height of first cylinder = 5y

height of second cylinder = 3y

ratio of volumes between them

= (2πr^2h)/(2πr^2h)

= {2x 22/7 (2x)^2 (5y)} / {2x22/7 (3x)^2(3y)}

( 2, 22/7 cancelled by each other)

= 4x^2 (5y) / 9x^2 (3y)

(x^2 and y cancelled by each other)

= (4x 5)/ (9x3)

= 20/ 27

ratio between them is 20:27

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Answered by kavya666666
41

Answer:

The radii of two cylinders are in the ratio 2:3 and their heights are in the ratio 5:3 . The ratio of their volumes is. Step by step solution by experts to help you in doubt clearance & scoring excellent marks in exams. =π×(2r)2×5hπ×(3r)2×3h=2027.

Step-by-step explanation:

Correct option is

D

20:27

As radii of two cylinder in in ratio of 2:3

So radius of 1st cylinder=2r

radius of 2st cylinder=3r

heights are in the ratio 5:3.

height of 1st cylinder=5h

height of 2st cylinder=3h

ratio of volume=volume of 1st cylinder/volume of 2nd cylinder

V=Π(2r)

2

∗5h/Π(3r)

2

∗3h

V=20rh/27rh

V=20/27

.

are you in class 8th ?

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