answer it plz 10 point question
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BGF = 90* so now it can help you out .
anshuman10506:
solution also plz
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Given:-
ΔABC is a right angled triangle at B.
ADEC & BCFG are squares.
Formulas used :-
1) Euler's addition axiom
2) Simple geometrical logic
3) Triangle Congruence
Proof:-
Let us consider the triangles ACF & BCE for our proof.
∠BCF = ∠ACE ------(each 90° since angles of squares)
Now, adding ∠ACB on both sides, we get
∠ BCE = ∠ ACF -------(i)
Now,
BC = CF & AC = CE ----(adjacent sides of squares are equal)
-------(ii)
So, from (i) and (ii)
ΔECB ≅ ΔACF ----(congruent by S-A-S rule)
(Side-Angle-Side rule of congruency of triangles)
∴ AF = BE ----(by C-P-C-T)
( corresponding parts of congruent triangles are equal)
Hence, proved.
Hope this helps you !
#Dhruvsh
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