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60°
Step-by-step explanation:
Extend OP to A and RS to B such that OA║ SB
∠BRO = 50 = 180 - 130 (linear pair)
let the point where PQ and RS intersect be L
∠BLP = 110 (corresponding angles)
∠PLR = 70 = 180 - 110 (linear pair)
In Δ QLR, through Angle sum property
∠PQR = 180 - (70 + 50) = 180 - 120 = 60
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