To divide a line segment AB in the ratio 5:6 , draw a ray AX such that angle BAX is an acute angle, then draw a ray BY parallel to AX and the points A1, A2, A3, ..... and B1, B2, B3, ..... are located at equal distances on ray AX and BY, respectively. Then which points are joined.
Explain with figure.
Answers
Answer:
A5 and B6
Step-by-step explanation:
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Given : A line segment AB is to be divided in the ratio 5: 6.
Ray AX is drawn such that ZBAX is acute.
Also ray BY is drawn parallel to AX and the points A1, A2, A3,... and B1, B2, B3,... are located at equal distances on rays AX and BY respectively.
To Find : Which two points now will be joined
Solution:
To divide a line segment AB in the ratio 5:6,
Step1 : Draw a line segment AB of some length
Step 2 : Draw a line segment AX such that ∠BAX is an acute angle
Step 3: Take 5 point on AX of Equal length one by one ( consecutively)
Step 4: Take 6 point on BY of Equal length (same as on AX) one by one
Step 5 : Join 5th Point on AX with 6th point on BY as a straight line intersecting AB at M
M divides AB in to 5 : 6 Ratio.
as AA₅M ≈ BB₆M using AAA
=> AA₅ /BB₆ = AM : BM
=> 5: 6 = AM : BM
Hence point M divided AB in 5 : 6 ratio
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