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l.h.s→52×48= (50+2)(50-2)
r.h.s→a^2-b^2=(a-b)(a+b)
evaluating lhs and rhs
a-b=50-2. a+b=50+2
or we can say that a=50&b=2. =Ans.
r.h.s→a^2-b^2=(a-b)(a+b)
evaluating lhs and rhs
a-b=50-2. a+b=50+2
or we can say that a=50&b=2. =Ans.
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Answered by
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We know that (a²-b²) = (a+b)x(a-b)
so we can write
a+b=52 and
a-b=48
adding both equations we get
2a=100
a=50
substituting in equation 1 we get
b=2
so we can write
a+b=52 and
a-b=48
adding both equations we get
2a=100
a=50
substituting in equation 1 we get
b=2
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