Question

answer itt..................?​

Answer 1

Answer;

we have sin A =12/13

=>sin²A=(12/13)²

=>1-cos²A=144/169

=>cos²A=1-144/169

=>cos²A=169-144/169

=>cos²A=25/169

=>cos A=√25/169=6/13

we know that

tan A=sin A/cos A=12/5

Answer 2

Answer:

$\sin(a) = 12 \div 13 \\ now \cos(a) = 5 \div 13 \\ \tan(a) = 12 \div 5$

hence cosA=5/13

tanA=12/5