Question

answer itttt

wrong answer will be reported ​

Answer 1

ABC is a isosceles triangle in which AB=AC

BD Perpendicular to AC

In △ABD

AB^2 =AD^2 +BD^2 ...(Pythagoras theoram)

∴AC^2 =AD^2 +BD^2....(as AB=AC) ...(1)

From diagram, we see that

⇒AC=CD+AD

⇒AC^2 =(CD+AD)^2

From (1) we get,

⇒(CD+AD)^2=AD^2 +BD^2

CD^2+AD^2 +2(CD×AD)=AD^2 +BD^2

CD^2 +2(CD×AD)=BD^2 ...(AD square gets cancelled from both sides)

BD ^2 −CD^2

=2(CD×AD)

Hence proved.

HoPe Ut HeLpS YoU(⌒_⌒;)(⌒_⌒;)✌✌

Answer 2

Answer:

by pythagoras theorem solve the question