Question

answer me 9th question pls I will surely mark u as brainlists​

Answer 1

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☃ ᴀɴꜱᴡᴇʀ ☃

Given y = aenx + be– nx y1

y^1 = aenx . n + be– nx (–n)

⇨ ane^nx – bne– nx y11

y^11 = ane^nx . n – bne– nx(–n)

⇨ an2 e^nx + bn2 e– nx

⇨ n2 (ae^nx + be^– nx) = n2y

∴ y^11 = n^2y

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Answer 2

Answer:

refer to this attachment ✅✅