Question

answer me as you can fast​

Answer 1

Answer:

(2a^3-b^3)^3-(b^3)^3

=(2a^3-b^3-b^3)(4a^6+b^6+2a^3b^6)

=(2a^3-2b^3)(4a^6+b^6+2a^3b^6)

=2(a^3-b^3)(4a^5+b^6+2a^3b^6)

=2(a-b)(a^2+b^2+ab)(4a^6+b^+2a^3b^6)

Answer 2

Step-by-step explanation:

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