Question

answer me buddies and explain it​

Answer 1

Answer:

The car stops after traveling 50m. So, from the laws of motion,

V^2=U^2+2D(-a)

where V is the velocity at the end

U us its initial velocity

D is the distance traveled before coming to rest after applying retarding force

a us the acceleration but negative because retarding.

So

0=20^2–2*50*a

Or, 100a=400

So, a=4 ms^-2

Since the mass of the car is 1000 kg. So

F=m*a

=1000*4

=4000N

So the applied force is 4000 Newton's

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