answer me buddies and explain it
Attachments:
Answers
Answered by
2
Answer:
The car stops after traveling 50m. So, from the laws of motion,
V^2=U^2+2D(-a)
where V is the velocity at the end
U us its initial velocity
D is the distance traveled before coming to rest after applying retarding force
a us the acceleration but negative because retarding.
So
0=20^2–2*50*a
Or, 100a=400
So, a=4 ms^-2
Since the mass of the car is 1000 kg. So
F=m*a
=1000*4
=4000N
So the applied force is 4000 Newton's
you have any more problem then contact on 9693451773
Similar questions