Question

answer me......fast and correct answers....​

Answer 1

Answer:

(i) Object distance, u=-60 cm

Focal length of the concave lens, f= -30 cm.

Using lens formula,

1 1 1

__ - __ = __

V u f

1 1 1

__ - ___ = ___

V (-60) -30

1 -1 1

= __ - ___ =____

V 30 60

1 - 3

__= ___

V 60

V=-20 cm

The image will be formed at a distance of 20 cm in front of the lens.

(ii) Nature of the image is virtual. The position of the image is between F1 and optical center 0. Size of the image is diminished. The image is Erect.

Answer 2

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force is any interaction that, when unopposed, will change the motion of an object. A force can cause an object with mass to change its velocity, i.e., to accelerate. Force can also be described intuitively as a push or a pull. A force has both magnitude and direction, making it a vector quantity