Math, asked by StarlightPhoenix, 2 days ago

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Answered by sandy1816
1

 \frac{ {cos}^{2}  \theta -  {cot}^{2}  \theta + 1}{ {sin}^{2}  \theta +  {tan}^{2}  \theta - 1}  \\ \\ =  \frac{ {cos}^{2}  \theta -  \frac{ {cos}^{2}  \theta}{ {sin}^{2} \theta } + 1 }{ {sin}^{2} \theta +  \frac{ {sin}^{2} \theta }{ {cos}^{2} \theta } - 1 }  \\  \\=  \frac{ \frac{ {cos}^{2} \theta {sin}^{2} \theta -  {cos}^{2} \theta +  {sin}^{2}    \theta }{ {sin}^{2}  \theta} }{ \frac{ {sin}^{2}  \theta {cos}^{2} \theta +  {sin}^{2}  \theta -  {cos}^{2}  \theta }{ {cos}^{2}  \theta} }\\  \\  =  \frac{ {cos}^{2} \theta }{ {sin}^{2}  \theta}\\  \\  =  {cot}^{2}  \theta

Answered by lingampellilavanya83
4

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hope it's helpful answer

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