Question

answer me fast if u know..​

Answer 1

Step-by-step explanation:

We have,

${x}^{3} - 6 {x}^{2} + 11x - 6 > 0$

$\implies {x}^{3} - {x}^{2} - 5 {x}^{2} +5x + 6x - 6 > 0$

$\implies {x}^{2} (x- 1) - 5x(x - 1) + 6(x - 1)> 0$

$\implies (x- 1)( {x}^{2} - 5x + 6)> 0$

$\implies (x- 1)( {x}^{2} - 3x - 2x + 6)> 0$

$\implies (x- 1) \{x(x - 3) - 2(x - 3) \}> 0$

$\implies (x- 1)(x - 2)(x - 3)> 0$

$\tt \pink{ \implies \: x \in(1 , 2) \: \cup \: (3 , \infty ) }$