Math, asked by gayu07, 1 year ago

answer me fast
kl meri exam hai

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Answered by chandresh126
1

Answer:


Hey Mate,


The relation

(sin x + cosec x)^2 + (cos x + sec x)^2 = 7 + tan^2 x + cot^2x

has to be proved.


Start with the LHS:


(sin x + cosec x)^2 + (cos x + sec x)^2


◆=> sin^2 X + cosec^2X + 2×sinX × cosecX + cos^2X + sec^2X + 2×cosX × secX


◆=> 1 + cosec^2x + 2 + sec^2x + 2


◆=> 1 + 1 + cot^2x + 2 + 1 + tan^2x + 2


◆=> 7 + cot^2x + tan^2x


●This proves that (sin x + cosec x)^2 + (cos x + sec x)^2 = 7 + tan^2 x + cot^2x


Thank-you


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Answered by gayu50
1
thank you friends I have changed my name
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