Question

answer me guys urgent​

Answer 1

Step-by-step explanation:

$\frac{(8-i)}{(3-2i)}$

$From \: rationalisation-$

$\frac{(8-i)(3+2i)}{(3-2i)(3+2i)}$

$\frac{(24+16i-3i-2i²)}{(3)²-(2i)²}$

$\frac{(24+13i-2(-1))}{(9-4i²)}$

$\frac{(24+13i+2)}{9-4(-1)}$

$\frac{26+13i}{9+4}$

$\frac{26+13i}{13}$

$=> (2 + i)$

$Comparing it from (a+bi)$

$a = 2$

$b = 1$

Answer 2

Answer:

dont know

Step-by-step explanation:

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