find the average of forst 40 natural numbers?
Answers
Answered by
4
Answer:
the average of first 40 natural numbers= 41/2 = 20.5
Step-by-step explanation:
A.P: 1,2,3....40
here, a= 1; an= 40; d= 1; n=40
Sn= n/2(a + an)
Sn= 20(1+40)
Sn= 20 + 800
Sn= 820
Therefore, average of 40 natural numbers= Sn/40
=> 820/40
=> 41/2
Answered by
0
Answer:
20.5
Step-by-step explanation:
1+2+3+4+5+6+7+8+9............+40/40
a=1 , n=40 An=40
Sn= n/2(a+An)
Sum of first 40 neutral number is 820.
Average=820/40
=20.5
I hope you understood.
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