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9. R= 25 ohm ; v= 10 v ; i= v/ r = 10/25= 0.4ampere
current remain same in series ...
10. i) 12 ohm
ii) i= v/ r = 6/12 = 0.5 ampere
iii) potential diff across 4 ohm= 0.5× 4= 2 volt
potential diff across 8 ohm= 0.5×8= 4 volt
hope gonna help
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2 vlt and 4 vlt is your answer mate
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