Question

The middle digit of a number between 100 and 1000 is zero and the some of the digits is 11 if the digits are interchanged the number so formed exceeds the original number by 495 find the number​

Answer 1

Answer:

>> Let the number in 100s digit be x,

>> and the number in 1s digit be y,

Then,the number would be x0y : 100x+y

Condition 1: Sum of the digits : x+y=11.....(i)

If it is reversed ,it would be y0x : 100y+x,

Given The difference between them: 100x+y -(100y+x) = -495

100x+y-100y-x =-495

99x-99y = -495 (divided by 99)

x-y=-5.....(ii)

Adding (i) and (ii), we get,

(x+y)+(x-y)=11+(-5)

x+y+x-y=11-5

2x=6

∴ x=3

Substituting value of x in (i),

x+y=11

3+y=11

y=11-3

∴ y=8

∴The number is 308

Answer 2

308 is the number DUDE. 》》》》☆☆