answer me plz answer question no. 9
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Answered by
1
Here you know that diagonals of a rhombus perpendicularly bisect each other
So,
BO=8 cm
Using pythagoras theorem,
AO ^2 + AB ^2 = AB^2
AO * AO = 10* 10 - 8 *8
AO= √36
AO=6cm
Therefore,
AC = 12 cm
Please mark brainliest
So,
BO=8 cm
Using pythagoras theorem,
AO ^2 + AB ^2 = AB^2
AO * AO = 10* 10 - 8 *8
AO= √36
AO=6cm
Therefore,
AC = 12 cm
Please mark brainliest
Answered by
0
dc = 10 cm
do = 8 cm
co = sq rate of 10 sq - 8 sq = 100- 64 = 36 and sq root if 36 = 6 cm
other diagnol = 6+6 = 12cm
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