Math, asked by aditya3133, 1 year ago

answer me plz answer question no. 9​

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Answers

Answered by vivu
1
Here you know that diagonals of a rhombus perpendicularly bisect each other

So,

BO=8 cm

Using pythagoras theorem,

AO ^2 + AB ^2 = AB^2

AO * AO = 10* 10 - 8 *8

AO= √36

AO=6cm

Therefore,

AC = 12 cm

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Answered by tarunsmart
0

dc = 10 cm

do = 8 cm

co = sq rate of 10 sq - 8 sq = 100- 64 = 36 and sq root if 36 = 6 cm

other diagnol = 6+6 = 12cm

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