Question

answer me. RS Aggarwal Q

Answer 1

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ɧeՐe ɿՏ ՎԾՄՐ

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⊙ In triangle AOB

Angle AOB = 90°


so, Angle BoC = 180-90=90°


Now ,



Angle OBC = 35°



So,


90+35+ACB = 180°


ACB = 180-125= 55°



so, it is 55°



$hope \: it \: helps$




$<marquee > prabhudutt$

Answer 2

Here is your answer:

_____________________________

angle BAD = 90°

[ angle subtended by a semi circle is 90° ]

angle BAC + angle CAD = angle BAD

Given,

angle BAC = 70°

So: 70° + angle CAD = 90°

==> angle CAD = 90° - 70°

==> angle CAD = 20°...................................(1)

We know that:

angle DBC = angle CAD

[ angle subtended by the same arc are equal ]

angle DBC = 20° [See (1) ]

angle CBA =angle DBC + angle DBA

==> angle CBA = 20°+35°

==> angle CBA = 55°..................................(2)

angle ACB +angle CBA + angle CAB = 180°

[ Angle sum property of triangles ]

==> angle ACB + 55° + 70° = 180° [See (2)]

==> angle ACB + 125° = 180°

==> angle ACB = 180°-125°

==> angle ACB = 55°

Hence your answer is 55°

Hope it helps you mate!

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