Question

answer me this question of two similar triangles

Answer 1

Step-by-step explanation:

Given: ΔABC~ΔDEF

To Find: AB,BC,AC,DE,EF,DF

Proof: Now as ΔABC~ΔDEF,

AB/DE=BC/EF=AC/DF

x-1/8=2x+2/3x+9=4x/8x

Equating First and last,

x-1/8=1/2

2x-2=8

x=5

AB=x-1

    =4

BC=2x+2

    =12

AC=4x

    =20

DF=8x

   =40

EF=3x+9

   =24