Answer my question and I will mark you as Brainliest if i understood. The question isn't too tough.
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Answer:
Yes,
Step-by-step explanation:
In ∆ABD and ∆ DBC
AD=DC(given)
AB=BC(given)
BD=BD(common)
therefore, ∆ABC congruent to ∆DBC(SSS criteria)
=> angle ABC =angle CBD(c.p.c.t.)
hence BD bisects angle ABC.
hope it helped buddy have a great day
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