Math, asked by manisha87854, 11 months ago

answer my question fast!!!​

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Answered by Anonymous
2

Heya!.., here is your answer....

(i)

(2 -  \sqrt{5})

is an irrational no.

(ii)

(3 +  \sqrt{23}) -  \sqrt{23}   \\  \\  \:  \:  = 3 +  \sqrt{23}  -  \sqrt{23}  \\  \\  \:  \:  = 3

Therefore it is rational.

(iii)

((2 \sqrt{7})   \div   (7 \sqrt{7})) \\  \\  \:  \:  = (2 \div 7)

Therefore it is rational.

(iv)

(1  \div  \sqrt{2})

is an irrational no.

(v)

2\pi

is an irrational no.

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Answered by rajagoud22
0

hey buddy here is your answer

please mark brainlist

Step-by-step explanation:

i)2-root 5

=2 root 5 that is irrational

ii)3+root23 -root 23

=root 23 -root 23 is 0

so result is 3 that is rational as it is in the form of p/q

iii)2root7/2root7

=root 7 is cancelled by root 7

so the result is2by 2 that is 1 and rational as it is in the form of p/q

iv)1 upon root 2

is irrational

v)2pi

is irrational as pi is irrational please follow

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