Question

answer my question if you know only​

Answer 1

Here,

First term of AP = 22

Given,

$\bf{a_n = a + (n - 1)d} = - 11\\ \\ \to \tt22 + ( n- 1)d = - 11 \\ \to \tt(n - 1)d = - 11 - 22\\ \to \tt(n - 1)d = - 33\\ \\ </p><p> \bf</p><p>S_n = \frac{n}{2} \bigg\{2a + (n - 1)d \bigg\} = 66 \\ \\ \to \tt \frac{n}{2} \bigg(2 \{ 22\} + \{ - 33\}\bigg) = 66 \\ \\ \to \tt \frac{n}{2}\bigg(44 - 33 \bigg) = 66 \\ \\ \to \tt \frac{n}{2} (11) = 66 \\ \\ \to \tt \: \: n = \frac{66}{11} \times 2 \\ \\ \to \tt \: \: \: n = 6 \times 2 = 12$

Hence,

• Value of n is 12

Answer 2

Answer:

(A) 12 is the answer.........