Math, asked by komalsingrajput, 1 year ago

answer my question no 21 ka Or part ?

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Answers

Answered by palakhanduja32
1
volume of sphere=4/3pir^3 ,diameter=21
radius=21/2
4/3×22/7×21/2×21/2×21/2 =4851

radius of cone = 7/2
height= 3cm
volume of cone= 1/3pir^2h
1/3×22/7×7/2×7/2×3= 38.5cm^3

number of cones formed= volume of sphere/volume of cone

= 4851/38.5= 126

hope it helps you.
please mark it as brainliest.
Answered by TR0YE
0
⛦Hᴇʀᴇ Is Yoᴜʀ Aɴsᴡᴇʀ⚑
▬▬▬▬▬▬▬▬▬▬▬▬☟

➧ Diameter➙ 21 cm

➧ So, Radius➙ 21 / 2 cm

➧ Radius of cone
➾ 7/2 cm

➧ Height of cone
➾ 3 cm

➧ Volume of sphere =
No. of cones x Volume of cone

4/3 x 22/7 x 21/2 x 21/2 x 21/2 =

No. of cones x 1/3 x 22/7 x 7/2 x 7/2 x 3

➧ That implies,

11 x 441 = no. of cones x 77/2

4851 = no. of cones x 77/2

4851 x 2/77 = no. of cones

➧ So, No. of cones
➾ 126 ...✔

_________
Thanks...✊
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