answer my question no 21 ka Or part ?
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volume of sphere=4/3pir^3 ,diameter=21
radius=21/2
4/3×22/7×21/2×21/2×21/2 =4851
radius of cone = 7/2
height= 3cm
volume of cone= 1/3pir^2h
1/3×22/7×7/2×7/2×3= 38.5cm^3
number of cones formed= volume of sphere/volume of cone
= 4851/38.5= 126
hope it helps you.
please mark it as brainliest.
radius=21/2
4/3×22/7×21/2×21/2×21/2 =4851
radius of cone = 7/2
height= 3cm
volume of cone= 1/3pir^2h
1/3×22/7×7/2×7/2×3= 38.5cm^3
number of cones formed= volume of sphere/volume of cone
= 4851/38.5= 126
hope it helps you.
please mark it as brainliest.
Answered by
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⛦Hᴇʀᴇ Is Yoᴜʀ Aɴsᴡᴇʀ⚑
▬▬▬▬▬▬▬▬▬▬▬▬☟
➧ Diameter➙ 21 cm
➧ So, Radius➙ 21 / 2 cm
➧ Radius of cone
➾ 7/2 cm
➧ Height of cone
➾ 3 cm
➧ Volume of sphere =
No. of cones x Volume of cone
4/3 x 22/7 x 21/2 x 21/2 x 21/2 =
No. of cones x 1/3 x 22/7 x 7/2 x 7/2 x 3
➧ That implies,
11 x 441 = no. of cones x 77/2
4851 = no. of cones x 77/2
4851 x 2/77 = no. of cones
➧ So, No. of cones
➾ 126 ...✔
_________
Thanks...✊
▬▬▬▬▬▬▬▬▬▬▬▬☟
➧ Diameter➙ 21 cm
➧ So, Radius➙ 21 / 2 cm
➧ Radius of cone
➾ 7/2 cm
➧ Height of cone
➾ 3 cm
➧ Volume of sphere =
No. of cones x Volume of cone
4/3 x 22/7 x 21/2 x 21/2 x 21/2 =
No. of cones x 1/3 x 22/7 x 7/2 x 7/2 x 3
➧ That implies,
11 x 441 = no. of cones x 77/2
4851 = no. of cones x 77/2
4851 x 2/77 = no. of cones
➧ So, No. of cones
➾ 126 ...✔
_________
Thanks...✊
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