Math, asked by googleboy1, 1 year ago

answer my question please

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Answered by Samu1y
2
9x²-9(a+b)x+(2a²+5ab+2b²)=0

consider,
(2a²+5ab+2b²)
⇒2a²+4ab+ab+2b²
⇒2a(a+2b)+b(a+2b)
⇒(2a+b)(a+2b)

now,
9x²-9(a+b)x+(2a+b)(a+2b)=0
9x²-3(2a+b)x-3(a+2b)x+(2a+b)(a+2b)=0
3x(3x-(2a+b))-(a+2b)(x-(2a+b))=0
(3x-(a+2b))(3x-(a+2b))=0
∴x=(a+2b)/3  and x=(2a+b)/3

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