Question

Answer my questions pls.... ​

Answer 1

Answer:

U already wrote the answers, now what do u want dear..

No Ideas

Answer 2

Step-by-step explanation:

1) in triangle AOB AO = BO = radius

therefore triangle AOB is an isosceles

therefore angle BAO = OBA = 25

similarly in triangle BOC angle BCO = angle CBO = 35

and angle ABC = angle ABO + angle CBO = 60

therefore angle AOC = 2× 60 = 120 { angle made by same arc on centre of circle is double of angle made on same segment }

2) by using Pythagoras theorem

${x}^{2} = {5}^{2} - {4}^{2} = 9$

x = 3

4) by using same concept as in question 1 we can prove triangle ABO is an isosceles triangle

angle ABC = 40 + 56 = 96

NOTE - 5 points are not sufficient for answering all questions