if A(4,3) B(-1,y) and C(3.4) are the vertices of a right angled triangle ABC angle A=90°then find the value of the y
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Step-by-step explanation:
SOLUTION:-
As this is a right angle triangle, then
AC^2+AB^2=BC^2
By using distance formula we get,
[{(4-3)^2}+{(3-4)^2}]^2+[{(4+1)^2}+{(3-y)^2}]^2=[{(3+1)^2}+{(4-y)^2}]^2
By solving this we get the value of y
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