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Given
DEIIAB
AD=2x
DC=x+3
CE=x
BE=2x-1
By Basic Proportionality Theorm,
AD/DC=BE/EC
Substituting Values,
2x/x+3=2x-1/x
Cross. Multiplying,
2x^2=2x-1(x+3)
2x^2=2x^2+6x-x-3
Cancelling 2x^2 on both sides and transposing 3 to left hand side
3=6x-x
3=5x
X=3/5
So, therefore, x=0.6
Hope it helps, Pls Mark it as Brainliest
DEIIAB
AD=2x
DC=x+3
CE=x
BE=2x-1
By Basic Proportionality Theorm,
AD/DC=BE/EC
Substituting Values,
2x/x+3=2x-1/x
Cross. Multiplying,
2x^2=2x-1(x+3)
2x^2=2x^2+6x-x-3
Cancelling 2x^2 on both sides and transposing 3 to left hand side
3=6x-x
3=5x
X=3/5
So, therefore, x=0.6
Hope it helps, Pls Mark it as Brainliest
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