Question

answer of this question​

Answer 1

(d) obtion is right

HOPE THIS HELPS YOU

Answer 2

Answer:

As they are in AP their common difference will be same

so  ㏒3(2∧x -5) - ㏒3(2) = log3(2∧x-7/2) - ㏒3(2∧x -5)

⇒ ㏒3{(2∧x -5)/2}=log3{(2∧x-7/2)/(2∧x -5)}

⇒(2∧x -5)/2=(2∧x-7/2)/(2∧x -5)

⇒(2∧x -5)²=2∧x × 2  -  7

let 2∧x be a

⇒ (a-5)²= (2a-7)

⇒a²-12a+32=0

⇒(a-4)(a-8)=0

∴2∧x=4 or 2∧x =8

so, x=2 or x=3

∴option (d) is correct