Question

answer of this question ib a clear way​

Answer 1

Solution

(x+k) is a factor of x²+px+q and x²+lx+m

therefore.... applying the remainder theorem

x+k=0

=>x=-k

now ...

F1(x)=x²+px+q

=>F1(-k)=(-k)²+p(-k)+q=k²-pk+q=0.........(i)

and

F1(x)=x²+lx+m

=>F2(-k)=(-k)²+l(-k)+m=k²-lk+m=0..........(ii)

doing (i)-(ii)

=> k²-pk+q-(k²-lk+m)=0

=>k²-pk+q-k²+lk-m=0

=>k(l-p)=m-q

=>k=(m-q)/(l-p)

hope this helps you....

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