ANSWER OF THIS QUESTION IS (X-1)(X²+X-5)..give me soultion...please.
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FROM THE QUESTION,
( x - 1 ) IS A FACTOR OF x ³ - 6x + 5
THEREFORE , x - 1 = 0
===========> x = 1 .................( ⅰ )
SUBSTITUTE EQ (ⅰ) IN x ³ - 6x + 5 = 0
(1) ³ - 6(1) + 5 = 0
1 - 6 + 5 = 0
0 = 0
LHS = RHS
HENCE PROVED
( x - 1 ) IS A FACTOR OF x ³ - 6x + 5
THEREFORE , x - 1 = 0
===========> x = 1 .................( ⅰ )
SUBSTITUTE EQ (ⅰ) IN x ³ - 6x + 5 = 0
(1) ³ - 6(1) + 5 = 0
1 - 6 + 5 = 0
0 = 0
LHS = RHS
HENCE PROVED
hammad52:
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I don't understand hindi man
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i need this answer i ask in question
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what ........
0=0 noooo
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