Question

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A liquid is flowing in streamline manner in a pipe1 with rate of x. If the same liquid is flowing in a pipe of radius half of pipe 1 and length twice the pipe 1 with same pressure difference, the rate of
flow of liquid for this pipe is......​

Answer 1

Answer:

The rate of flow of liquid will be halved..

Explanation:

We don't know the initial rate of flow of liquid only that it is x

So let us assume the radius is r and the length of pipe can be the height as well which we assume is h.

We apply the formula,

Area = π × r^2 × h

=πr^2h

We know radius is halved, i.e.

r = r/2

And

h = 2h

Area = πr^2h

= π × (r/2)^2 ×2h

= (πr^2h)/2

Since the new area is half of initial area, the area available to water would be half in the new case.

Thus, rate of flow of water would be halved..

HOPE IT HELPS...

Answer 2

Answer:

greetings

Explanation:

The question statement is abit having some typo errors.

We know the initial rate of flow of liquid only that it is x

So let us assume the radius is r and the length of pipe can be the height as well which we assume is h.

We apply the formula,

Area = π × r^2 × h

Now as stated ,  radius is halved and pipe length doubled;

r = r/2

And

h = 2h

Area = πr^2h

= π × (r/2)^2 ×2h

= (πr^2h)/2

Since the new area is half of initial area, the area available to water would be half in the new case.

Thus, rate of flow of water would be halved