Question

ANSWER ONLY IF YOU ARE SURE WITH STEPS​

Answer 1

Resistance between XAY = (1 + 1 + 1) = 3Ω

Resistance between XY = 2Ω

Resistance between XBY = 6Ω

Let ' R be the net resistance between points X and Y

Then, 1/R' = 1/2 + 1/3 + 1/6 = (3 + 2 + 1)/6 = (6/6)Ω

Or, RI = 1Ω

Thus, we can say that between points A and B,

Three 1 Ω resistors are connected in series.

Let RAB be the net resistance between points A and B.

Then, RAB = ( 1 + 1 + 1)Ω = 3Ω