Question

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A battery of e.m.f. 15 V and internal resistance 3 ohm is connected to two resistors of resistances 3 ohm and 6 ohm in series.

Find =>>
1) the current through the battery

2) the potential difference between the terminals of the battery

Answer 1

current
E=I×(R+r)
I=E/(r+R)
I=15/12
I=5/4
I=1.25Ampere


Potential Difference between terminal
V=IR
1.25×9
11.25V