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The value of y is 15 and x is 60.
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Given:
In ∆ ABC, <A=x° , <CBD=7y° and <C=3y°, <CBA=5y°.
To Find:
⚫Value of x=?
Solution:
<A+<C+<CBA=180°...... (Sum of all angles of a triangle)
: . x+3y+5y=180°
: . x+8y=180°................... (1)
Here, <CBA is an exterior angle of a ∆ABC.
So, By Exterior angle of a triangle,
<CBA=<C+<A
: . 7y=3y+x
: . =7y-3y=x
: . x=4y
Now, substituting the value x in (1),
4y+8y=180°
12y=180°
y=180/12
y=15.
Now substituting the value of y in (1) we get,
x+8(15) =180°
x+120=180°
x=180-120
x=60.
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So the value of x is 60°.
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In ∆ ABC,
<A=x°=60°
<C=3y°=3(15) =45°
<B=5y°=5(15) =75°
<CBD=7y=7(15) =105°
#Siddhi
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