Chemistry, asked by Mastercard009, 3 months ago

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Answered by vrstuti0612
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When the pressure on a sample of a dry gas is held constant, the Kelvin temperature and the volume will be in direct proportion.[1]

This relationship of direct proportion can be written as:

{\displaystyle V\propto T}{\displaystyle V\propto T}

So this means:

{\displaystyle {\frac {V}{T}}=k,\quad or\quad V=kT}{\displaystyle {\frac {V}{T}}=k,\quad or\quad V=kT}

where:

V is the volume of the gas,

T is the temperature of the gas (measured in kelvins),

and k is a non-zero constant.

This law describes how a gas expands as the temperature increases; conversely, a decrease in temperature will lead to a decrease in volume. For comparing the same substance under two different sets of conditions, the law can be written as:

{\displaystyle {\frac {V_{1}}{T_{1}}}={\frac {V_{2}}{T_{2}}}\qquad {\text{or}}\qquad {\frac {V_{2}}{V_{1}}}={\frac {T_{2}}{T_{1}}}\qquad {\text{or}}\qquad V_{1}T_{2}=V_{2}T_{1}.}{\displaystyle {\frac {V_{1}}{T_{1}}}={\frac {V_{2}}{T_{2}}}\qquad {\text{or}}\qquad {\frac {V_{2}}{V_{1}}}={\frac {T_{2}}{T_{1}}}\qquad {\text{or}}\qquad V_{1}T_{2}=V_{2}T_{1}.}

The equation shows that, as absolute temperature increases, the volume of the gas also increases in proportion.

History

Relation to absolute zero

Relation to kinetic theory

See also

References

Further reading

External links

Last edited 14 days ago by Monkbot

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