Question

Answer please answer please
Question from Maths ​

Answer 1

Given:-

• Body moving in a circular path of radius 14 m.

To find :-

• Displacement after half tern.

Procedure:-

Since displacement is the shortest distance between initial and final position, it will result result to the diameter of circle.

The diameter of circle is 2 × Radius = 2 × 14 = 28m

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$\sf Circumference = 2 \pi rCircumference = 2πr$

$\sf \implies Circumference \ of \ the \ circular \ path = 2 \times \dfrac{22}{7} \times 14$

$\sf \implies Circumference \ of \ the \ circular \ path = 2 \times 22 \times 2$

$\sf \implies Circumference \ of \ the \ circular \ path = 88m$

Total path particle will cover = 88m

Half of total path = 88/2

$\: \: \:\:\: \: \circ \: \underline{\boxed{\red{\scriptsize{ \sf ∴\:Distance\: = \:44 \:m}}}}$

Answer 2

$\sf\red{Circumference=2πr}$

$\implies$$\sf{2 \times \frac{22}{7} \times 14}$

$\implies$$\sf{2×22×2}$

$\implies$$\sf{88\:m}$

$\sf\red{Half \: of \: total \: path =\frac{88}{2}=44\:m}$