Question

Answer please__half of a herd of deer are grazing in the field and three fourth of the remaing are playing nearby. the rest 9 are drinking water from the pond find the number of deer in the herd

Answer 1

Given,
1/2
of herd are grazing
3/4th
are playing
rest remaining 9
are drinking water.
If number of deer= x

Then we can say that half of the Deers were grazing and 3/4th of the other half were playing and 9 deers were drinking.

Therefore,
$\frac{1}{2} x + (\frac{3}{4} \times \frac{1}{2} x)+ 9 = total \: deers$
$\frac{1}{2} x + \frac{3x}{8} + 9 \\ \frac{4x}{2 \times 4} + \frac{3x}{8} + 9 \\ \frac{7x}{8} + 9 \\ \frac{7x + 72}{8} = x \\ 7x + 72 = 8x \\ 72 = 8x - 7x \\ x = 72$

Total number of deers would be 72

Answer 2

Answer:

the number of deers in the herd are 72

Step-by-step explanation:

let the number of deers in the herd = X

no. of deers grazing in the field = X/2

no. of deers playing nearby = 3/4 of X/2

                                           = (3/4)(X/2)

                                           = 3 X / 8

no. of deers drinking water from nearby pond = 9

according to the question,

9 + X/2 + 3 X / 8 = X

9 + 4 X/8 +3 X/8 = X

9 + 7 X/8 = X

9 = X - 7 X/8

9 = 8 X/8 - 7 X/8

9 = X/8

X = 8×9

X = 72

total number of sheeps = 72