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Answer: No . Of coins above 7th coin from the bottom = 3 coins
As rhe system is in equilibriul, force exerted by 7 th coin on 8th coin from the bottom= weight of 3 coins above it = 3*10*10/1000 = 0.3N
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Answer:mass above 7th coin from bottom =0.03kg (\frac{30gm}{1000gm})
as Force = Weight
w=mg\\=0.03kg(10m/s)\\=0.3 kgm/s \ or \ 0.3N
C
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