Math, asked by nandishironman, 11 months ago

Answer please:
Maths - Linear in One Variable​

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Answers

Answered by kingraj42
1

Step-by-step explanation:

let the numerator be x-3

denominator=x

condition=

 \frac{3(x - 3)}{x - 20}  =  \frac{1}{8}

 \frac{3x - 9}{x - 20}  =  \frac{1}{8}

8(x-20)=3x-9

8x-160=3x-9

8x-3x=-9+160

5x=151

x=151/5

denominator=151/5

numeratior=151/5-3

151-15 /3

=134/3

doubtful question. don't report if this is wrong

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