Math, asked by Mithil1000, 10 months ago

answer please this 3 Q​

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Answered by RagaviRagavendra
2

Heya

 2x-1= \frac {1}{x}

x(2x - 1) = 1 \\ 2x {}^{2}  - x = 1 \\ 2x {}^{2}  - x - 1 = 0 \\ 2x {}^{2}  - 2x + x - 1 = 0 \\ 2x(x - 1) + 1(x - 1) = 0 \\ (2x  + 1)(x - 1) = 0 \\  \\ now... \\

 2x+1=0

 x= \frac {-1}{2}

 x-1=0

 x= 1

Hope it helps you

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Answered by sam42005
0

......It is so easy..... can't tell

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